Question
Evaluate $\sqrt{3}$ correct up to two places of decimal.
✓
Answer
$\begin{array}{c|c}&1.732\\\hline1&\bar{3}\ \overline{00}\ \overline{00}\ 00\\1&1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\\hline27& 200\ \ \ \ \ \ \ \ \ \ \ \\\ 7&189\ \ \ \ \ \ \ \ \ \ \\\hline343\ \ \ & \ \ \ \ \ \ \ \ 1100\ \ \ \ \ \ \ \ \ \ \ \ \\\ 3&1029\ \ \ \\\hline3462\ \ \ \ \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 7100\ \ \ \ \ \ \ \ \ \ \ \ \ \\\ 2&\ \ \ \ \ 6924 \\\hline&\ \ \ \ \ \ 176\\\end{array}$ $\sqrt{3}=1.732$
Therefore, the value of $\sqrt{3}$ up to two places of decimal is $1.73.$
Therefore, the value of $\sqrt{3}$ up to two places of decimal is $1.73.$
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