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Complementary Angles — MATHEMATICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9MATHEMATICSComplementary Angles2 Marks
Question
Evaluate$: \tan (55^\circ - A) - \cot (35^\circ + A)$
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Answer

$\tan (55^\circ - A) - \cot (35^\circ + A)$
$= \tan [90^\circ - (35^\circ + A)] - \cot (35^\circ + A)$
$= \cot (35^\circ + A) - \cot (35^\circ + A)$
$= 0.$

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