Question
Factorise$ :a^6+ 27b^3$

Answer

$a^6+ 27b^3$
$= ( a^2 )^3 + ( 3b )^3$
$= ( a^2 + 3b )[ (a^2)^2 - a^2 x 3b + (3b)^2 ] [ \because a^3 + b^3 = ( a + b )( a^2 - ab + b^2 )]$
$= ( a^2 + 3b )[ a^4 - 3a^2b + 9b^2 ]$

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