Question
Evaluate the following: $102 \times 106$
✓
Answer
Here, we will use the identity $(x + a)(x + b) = x^2+ (a + b)x + ab.$
$102 × 106$
$= (100 + 2)(100 + 6)$
$= 100^2+ (2 + 6)100 + 2 × 6$
$= 10000 + 800 + 12$
$= 10812$
$102 × 106$
$= (100 + 2)(100 + 6)$
$= 100^2+ (2 + 6)100 + 2 × 6$
$= 10000 + 800 + 12$
$= 10812$
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