Question
Evaluate the following:
$^6\text{P}_6$

Answer

We have,
$^6\text{P}_6 = \frac{6!}{(6-6)!}\Big[\because^\text{n}\text{P}_\text{r}=\frac{\text{n!}}{(\text{n}-\text{r})!}\Big]$
$=\frac{6!}{0!}$
$= \frac{6\times5\times4\times3\times2\times1}{1}$
$= 720$
Hence, $^6\text{P}_6= 720$

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