Question
Evaluate the following:
$(98)^3$
$(98)^3$
✓
Answer
We know that $(a - b)^3 = a^3 - b^3 - 3ab(a - b)4
$\Rightarrow (98)^3$ can be written as $(100 - 2)^34
Here,$a = 100 and b = 2$
$(98)^3 = (100 - 2)^3$
$= (100)^3 - (2)^3 - 3(100)(2)(100 - 2)$
$= 1000000 - 8 - (600 \times 102)$
$= 1000000 - 8 - 58800$
$= 941192$
The value of $(98)^3 = 941192$
$\Rightarrow (98)^3$ can be written as $(100 - 2)^34
Here,$a = 100 and b = 2$
$(98)^3 = (100 - 2)^3$
$= (100)^3 - (2)^3 - 3(100)(2)(100 - 2)$
$= 1000000 - 8 - (600 \times 102)$
$= 1000000 - 8 - 58800$
$= 941192$
The value of $(98)^3 = 941192$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If x = 3 and y = -1, find the values of the following using in identity:$\Big(\frac{5}{\text{x}}+5\text{x}\Big)\Big(\frac{25}{\text{x}^2}-25+25\text{x}^2\Big)$
→In the following, use factor theorem to find whether polynomial $g(x)$ is a factor of polynomial $f(x)$ or, not:
$f(x) = 3x^3 + x^2 - 20x +12, g(x) = 3x - 2$
→$f(x) = 3x^3 + x^2 - 20x +12, g(x) = 3x - 2$
The following bar graph shows the results of an annual examination in a secondary school.
Read the bar graph and choose the correct alternative in each of the following:
Read the bar graph and choose the correct alternative in each of the following:
- The pair of classes in which the results of boys and girls are inversely proportional are:
- VI, VIII
- VI, IX
- VII, IX
- VIII, X
- The class having the lowest failure rate of girls is:
- VI
- X
- IX
- VIII
- The class having the lowest pass rate of students is:
- VI
- VII
- VIII
- IX
Prove that:$\frac{(0.6^0)-(0.1)^{-1}}{\Big(\frac{3}{8}\Big)^{-1}\Big(\frac{3}{2}\Big)^{^3}+\Big(\frac{1}{3}\Big)^{-1}}=-\frac{3}{2}$
→Rationalize the denominator : $\frac{1}{\sqrt{7}+\sqrt{2}}$
→Factorise: $(x+2)(x-3)(x-7)(x-2)+64$
→Using factor theorem, show that $g(x)$ is a factor of $p(x)$, when $p(x) = 3x^3 + x^2 - 20x + 12, g(x) = 3x - 2$
→A hemispherical dome of a building needs to be painted. If the circumference of the base of the dome is $17.6cm$, find the cost of painting it, given the cost of painting is $Rs. 5$ per $100cm^2$
→Simplify : $4 \sqrt{12}-\sqrt{75}-7 \sqrt{48}$
→Prove that:$(\text{a}^{-1}+\text{b}^{-1})=\frac{\text{ab}}{\text{a}+\text{b}}$
→