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Trigonometric Ratios — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsTrigonometric Ratios2 Marks
Question
Evaluate the following:
$\cos48^\circ-\sin42^\circ$
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Answer

We have to find: $\cos48^\circ-\sin42^\circ$ Since $\cos(90^\circ-\theta)=\sin\theta$So, $\cos48^\circ-\sin42^\circ=\cos(90^\circ-42^\circ)-\sin42^\circ$
$=\sin42^\circ-\sin42^\circ$ $= 0$ So value of $\cos48^\circ-\sin42^\circ\text{ is }0$

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