Gujarat BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions1 Mark
Question
Evaluate the following: $\cot^{-1}\Big(\cot\frac{9\pi}{4}\Big)$
✓
Answer
We have $\cot^{-1}\Big(\cot\frac{9\pi}{4}\Big)$ $=\cot^{-1}\Big[\cot\Big(2\pi+\frac{\pi}{4}\Big)\Big]$ $=\cot^{-1}\Big(\cot\frac{\pi}{4}\Big)$ $=\frac{\pi}{4}$
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