Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow-1}\frac{\text{x}^3+1}{{\text{x}+1}}$

Answer

$\lim\limits_{\text{x}\rightarrow-1}\frac{\text{x}^3+1}{{\text{x}+1}}$ $=\lim\limits_{\text{x}\rightarrow-1}\frac{(\text{x}+1)\big(\text{x}^2-\text{x}+1\big)}{(\text{x}+1)}$ $\Big[\text{a}^3+\text{b}^3=(\text{a}+\text{b})\big(\text{a}^2+\text{b}^2-\text{ab}\big)\Big]$ $=\lim\limits_{\text{x}\rightarrow-1}{(\text{x}^2-\text{x}-1)}$ $=(-1)^2-(-1)+1$ $=1+1+1$ $=3$

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