Question
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow1}\Big(\frac{1}{\text{x}-1}-\frac{2}{\text{x}^2-1}\Big)$

Answer

$\lim\limits_{\text{x}\rightarrow1}\Big(\frac{1}{\text{x}-1}-\frac{2}{\text{x}^2-1}\Big)$ $=\lim\limits_{\text{x}\rightarrow1}\Big(\frac{1}{​​​​\text{x}-1}-\frac{2}{(\text{x}-1)(\text{x}+1)}\Big)$ $=\lim\limits_{\text{x}\rightarrow1}\Big(\frac{\text{x}+1-2}{(\text{x}-1)(\text{x}+1)}\Big)$ $=\lim\limits_{\text{x}\rightarrow1}\Big(\frac{\text{x}-1}{(\text{x}-1)(\text{x}+1)}\Big)$ $=\lim\limits_{\text{x}\rightarrow1}\Big(\frac{1}{(\text{x}+1)}\Big)$ $=\frac{1}{1+1}=\frac12$

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