Question
Evaluate the following limit:
$\lim\limits_{\theta\rightarrow0}\frac{1-\cos4\theta}{1-\cos6\theta}$

Answer

$\lim\limits_{\theta\rightarrow0}\frac{1-\cos4\theta}{1-\cos6\theta}$
$=\lim\limits_{\theta \rightarrow0}\frac{2\sin^22\theta}{2\sin^23\theta}$
$=\lim\limits_{\theta \rightarrow0}\frac{(\sin2\theta)^2}{(\sin3\theta)^2}$
$=\frac{\lim\limits_{\theta \rightarrow0}\big(\frac{\sin2\theta}{2\theta}\big)^2\times4\theta^2}{\lim\limits_{\theta \rightarrow0}\big(\frac{\sin3\theta}{3\theta}\big)^2\times9\theta^2}$
$=\frac{1\times4\theta^2}{1\times9\theta^2}$
$=\frac{4}{9}$

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