Question
Evaluate the following limits:

$\lim _{x \rightarrow 3}\left[\frac{\sqrt{2 x+6}}{x}\right]$

Answer

$
\begin{aligned}
\lim _{x \rightarrow 3} \frac{\sqrt{2 x+6}}{x} & =\frac{\lim _{x \rightarrow 3} \sqrt{2 x+6}}{\lim _{x \rightarrow 3} x} \\
& =\frac{\sqrt{2(3)+6}}{3} \\
& =\frac{\sqrt{12}}{3}=\frac{2 \sqrt{3}}{3}
\end{aligned}
$

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