Question
Evaluate the following : $\mathrm{i}^{35}$

Answer

We know that, $i^2=-1, i^3=-i, i^4=1$
$\mathrm{i}^{35}=\left(\mathrm{i}^4\right)^8\left(\mathrm{i}^2\right) \mathrm{i}=(1)^8(-1) \mathrm{i}=-\mathrm{i}$

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