Question
Evaluate the following: $\sin36^\circ\cos9^\circ+\cos36^\circ\sin9^\circ$

Answer

$=\sin(36^\circ+9^\circ)$ $[\sin(\text{A+B})=\sin\text{A}\cos\text{B}+\cos\text{A}\sin\text{B}]$ $=\sin45^\circ$ $=\frac{1}{\sqrt{2}}$

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