MCQ
Evaluate the integral :$\int {\frac{{\ln \,(6{x^2})}}{x}\,dx} $
- A$\frac{1}{8}{[\ln (6{x^2})]^3}+ C$
- ✓$\frac{1}{4}[{\ln ^2}(6{x^2})]+ C$
- C$\frac{1}{2}[\ln (6{x^2})]+ C$
- D$\frac{1}{{16}}{[\ln (6{x^2})]^4}+ C$
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