Question
Evaluate $x,y$ if $\left[\begin{array}{cc}3 & -2 \\ -1 & 4\end{array}\right]\left[\begin{array}{c}2 x \\ 1\end{array}\right]+2\left[\begin{array}{c}-4 \\ 5\end{array}\right]=\left[\begin{array}{c}8 \\ 4 y\end{array}\right]$

Answer

$\begin{array}{l}{\left[\begin{array}{cc}3 & -2 \\ -1 & 4\end{array}\right]\left[\begin{array}{c}2 x \\ 1\end{array}\right]+2\left[\begin{array}{c}-4 \\ 5\end{array}\right]=\left[\begin{array}{c}8 \\ 4 y\end{array}\right]} \end{array}$
${\left[\begin{array}{c}3 \times 2 x+(-2) \times 1 \\ -1 \times 2 x+4 \times 1\end{array}\right]+\left[\begin{array}{c}-8 \\ 10\end{array}\right]=\left[\begin{array}{c}8 \\ 4 y\end{array}\right]}  $
${\left[\begin{array}{c}6 x-2 \\ -2 x+4\end{array}\right]+\left[\begin{array}{c}-8 \\ 10\end{array}\right]=\left[\begin{array}{c}8 \\ 4 y\end{array}\right]}  $
$ {\left[\begin{array}{c}6 x-2-8 \\ -2 x+4+10\end{array}\right]=\left[\begin{array}{c}8 \\ 4 y\end{array}\right]}  $
$ {\left[\begin{array}{c}6 x-10 \\ -2 x+14\end{array}\right]=\left[\begin{array}{c}8 \\ 4 y\end{array}\right]}$
$6x - 10 = 8$
$\Rightarrow 6x = 18, x = 3$
$-2x + 14 = 4y$
$\Rightarrow -2x \ 3 + 14 = 4y$
$y=\frac{14-6}{4}$
$=\frac{8}{4}=2$
$x=3, y=2$

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