Download App

2. structure of atom — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry2. structure of atom1 Mark
MCQ
Excited hydrogen atom emits light in the ultraviolet region at $2.47 \times 10^{15}\,Hz.$ With this frequency, the energy of a single photon is $(h = 6.63 \times 10^{-34}\,Js)$
  • A
    $8.041 \times 10^{-40}\,J$
  • B
    $2.680 \times 10^{-19}\,J$
  • ✓
    $1.640 \times 10^{-18}\,J$
  • D
    $6.111 \times 10^{-17}\,J$
✓

Answer

Correct option: C.
$1.640 \times 10^{-18}\,J$
c
$E = hv$
$= 6.63 \times 10^{-34} \times 2.47 \times 10^{15}$
$= 1 .640 \times 10^{-18}\,J$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 2. structure of atom→2. structure of atom — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The first and second ionisation enthalpies of a metal are $496$ and $4560 \;\mathrm{kJ} \mathrm{mol}^{-1},$ respectively. How many moles of $\mathrm{HCl}$ and $\mathrm{H}_{2} \mathrm{SO}_{4}$ respectively, will be needed to react completely with $1$ mole of the metal hydroxide?
→
During the formation of a molecular orbital from atomic orbitals, probability of electron density is
→
Which of the following can give base $O{H^ - }$
→
$K_{sp}$ for $BaSO_4$ at $25\,^oC$ is $1.1 \times 10^{-10}$. To make the new solubility equal to $1.1 \times 10^{-8}$, it is necessary to use the solution of $Na_2SO_4$ of the following concentration....$M$
→
The one which has the highest value of $pH$ is
→
To carry out above conversion, $(A)$ and $(B)$ respectively, are
→
The standard enthalpy of formation of $NH_3$ is $- 46.0 \,kJ\, mol^{-1}.$ If the enthalpy of formation of $H_2$ from its atoms is $- 436\, kJ\, mol^{-1}$ and that of $N_2$ is $-  712 \,kJ\, mol^{-1},$ the average bond enthalpy of $N - H $ bond in $NH_3$ is ................ $\mathrm{kJ\,mol}^{-1}$
→
In the following sequence of reactions, the alkene affords the compound  $'B'$

$CH_3 - CH = CH - CH_3 \xrightarrow{{{O_3}}} A $$\xrightarrow[{Zn}]{{{H_2}O}} B.$

The compound $B$ is

→
Which of the following compounds has the lowest boiling point?
→
In which of the following reaction, product is not alkane
→