The first and second ionisation enthalpies of a metal are 496 and 4560 ;kJ mol^ -1 , respectively. How many moles of HCl and H_ 2 SO_ 4 respectively, will be needed to react completely with 1 mole of the metal hydroxide?

The first and second ionisation enthalpies of a metal are 496 and…

MCQ

The first and second ionisation enthalpies of a metal are $496$ and $4560 \;\mathrm{kJ} \mathrm{mol}^{-1},$ respectively. How many moles of $\mathrm{HCl}$ and $\mathrm{H}_{2} \mathrm{SO}_{4}$ respectively, will be needed to react completely with $1$ mole of the metal hydroxide?

✓
$1$ and $0.5$
B
$2$ and $0.5$
C
$1$ and $1$
D
$1$ and $2$

✓

Answer

Correct option: A.

$1$ and $0.5$

a
IE values indicate, that the metal belongs to Ist group since second IE is very high ( only one valence electron) Metal hydroxide will be of type, $MOH$. $\mathrm{MOH}+\mathrm{HCl} \rightarrow \mathrm{MCl}+\mathrm{H}_{2} \mathrm{O}$

$(1mol)$ $(1 \mathrm{mol})$

$\mathrm{MOH}+\frac{1}{2} \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \frac{1}{2} \mathrm{M}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O}$

$(1mol) $$\left(\frac{1}{2} \mathrm{mol}\right)$

So one mole of HCl required to react with one mole $MOH.$

So $\frac{1}{2}$ mole of $\mathrm{H}_{2} \mathrm{SO}_{4}$ required to react with one mole $MOH.$

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