Question
Expand the following:
$(-x+2 y-3 z)^2$
$(-x+2 y-3 z)^2$
✓
Answer
$(-x+2 y-3 z)^2=\{(-x)+2 y+(-3 z)\}^2$
$=(-x)^2+(2 y)^2+(-3 z)^2+2(-x)(2 y)+2(2 y)(-3 z)+2(-3 y z)(-x)$
$=x^2+4 y^2+9 z^2-4 x y-12 y z+6 x z$.
$=(-x)^2+(2 y)^2+(-3 z)^2+2(-x)(2 y)+2(2 y)(-3 z)+2(-3 y z)(-x)$
$=x^2+4 y^2+9 z^2-4 x y-12 y z+6 x z$.
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