Question
Expand using suitable identity: $(-2 x+3 y+2 z)^2$

Answer

$(-2 x+3 y+2 z)^2$
$=\{(-2 x)+3 y+(2 z)\}^2$
$=(-2 x)^2+(3 y)^2+(2 z)^2+2(-2 x)(3 y)+2(3 y)(2 z)+2(2 z)(-2 x)$
$\left(\text { Using Identity }(a+b+c)^2=a^2+b^2+c^2+2 a b+2 b c+2 c a\right)$
$=4 x^2+9 y^2+4 z^2-12 x y+12 y z-8 z x$

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