Question
Explain, by giving an example, how oxidation and reduction proceed side by side.

Answer

$\text{CuO}\ \ \ \ \ \ \ \ \ \ \ +\ \ \ \ \ \ \ \ \ \text{H}_2\ \ \xrightarrow{\ \ \ \ \ {\text{Heat}}\ \ \ \ \ \ }\ \ \text{Cu}\ \ \ \ \ \ \ +\ \ \ \ \text{H}_2\text{O}\\ ^\text{Copper Oxide}\ \ \ \ \ \ \ \ \ \ \ \ ^\text{Hydrogen}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{Copper}\ \ \ \ \ \ \ \ \ \ \ \ ^\text{Water}$
In this reaction, copper oxide is being reduced to copper whereas hydrogen is being oxidised to water.

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