Question
Explain clemmensen reaction with one example.
✓
Answer
⇒ Reduction to hydrocarbons: The carbonyl group of aldehydes and ketones is reduced to CH2 group when treated with zincamalgam and concentrated hydrochloric acid [Clemmensen reduction] or with hydrazine followed by heating with sodium or potassium hydroxide in high boiling solvent such as ethylene glycol (Wolff-Kishner reduction).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Explain the rate expression for a reaction in which stoichiometric coefficients of reactants and produch are not same or unit.
Explain Electrolysis of molten NaCl
Answer the following question:
Although phenoxide ion has more number of resonating structures than carboxylate ion, carboxylic acid is a stronger acid than phenol. Give two reasons.
Which of the following compounds (a) and (b) will not react with a mixture of NaBr and H2SO4. Explain why?
→- $\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}$
Explain the following phenomena with the help of Henry’s law.
Why soda water bottle kept at room temperature fizzes on opening?
Why soda water bottle kept at room temperature fizzes on opening?
Explain the structure of amine compounds by drawing a diagram.
Tarnished silver contains Ag2S. Can this tarnish be removed by placing tarnished silver ware in an aluminium pan containing an inert electrolytic solution such as NaCl? The standard electrode potential for half reaction:
$\text{Ag}_2\text{S(s) + 2e}^-\xrightarrow{\ \ \ \ \ \ \ }2\text{Ag(s) + S}^{2-}\text{is}-0.71\text{V}$
and for $\text{Al}^{3+}+3\text{e}^{-}\xrightarrow{ \ \ \ \ \ \ \ \ \ \ }2\text{Al(s) is}-1.66\text{V}$
→$\text{Ag}_2\text{S(s) + 2e}^-\xrightarrow{\ \ \ \ \ \ \ }2\text{Ag(s) + S}^{2-}\text{is}-0.71\text{V}$
and for $\text{Al}^{3+}+3\text{e}^{-}\xrightarrow{ \ \ \ \ \ \ \ \ \ \ }2\text{Al(s) is}-1.66\text{V}$
State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution?
The rate constant for the decomposition of hydrocarbons is 2.418 × 10–5s–1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.