Question
Explain density of Haloalkane Compound.
✓
Answer
→ Bromo, iodo and polychloro derivatives of hydrocarbons are heavier than water.
→ The density increases with increase in number of carbon atoms, halogen atoms and atomic mass of the halogen atoms.
→ Some density order of haloalkane compound is given below:
→ (1) CCI4 > CHCI3 > CH2Cl2 > CH3CI 4
→ (2) n - C3H7I > n - C3H7Br > n - C3H7CI
→ The density increases with increase in number of carbon atoms, halogen atoms and atomic mass of the halogen atoms.
→ Some density order of haloalkane compound is given below:
→ (1) CCI4 > CHCI3 > CH2Cl2 > CH3CI 4
→ (2) n - C3H7I > n - C3H7Br > n - C3H7CI
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Account for the following:
- Phenol does not react with NaHCO3 whereas carboxylic acids react.
- Phenol is more easily nitrated than benzene.
p-Dichlorobenzene has higher m.p. than those of $o$-and $m$-isomers. Discuss.
→Write common name and IUPAC name of following alcohol compound.
Given that the standard electrode potentials (Eo) of metals are:
K+/K = –2.93 V, Ag+/Ag = 0.80 V, Cu2+/Cu = 0.34 V,
Mg2+/Mg = -2.37 V, Cr3+/Cr = – 0.74 V, Fe2+/Fe = – 0.44 V.
Arrange these metals in an increasing order of their reducing power.
K+/K = –2.93 V, Ag+/Ag = 0.80 V, Cu2+/Cu = 0.34 V,
Mg2+/Mg = -2.37 V, Cr3+/Cr = – 0.74 V, Fe2+/Fe = – 0.44 V.
Arrange these metals in an increasing order of their reducing power.
What are the IUPAC names of the insecticide DDT and benzenehexachloride? Why is their use banned in India and other countries?
Write down chemical equations to prepare following substances from 1-Chloropropane.
What is expected Van't Hoff factor for $K _4\left[ Fe ( CN )_6\right]$ ?
→Differentiate between globular and fibrous proteins.
Write common name and IUPAC name of following alcohol compound.
CH3-CH2-CH2-CH2-OH
CH3-CH2-CH2-CH2-OH
Propose the mechanism for the following reaction:
$\text{CH}_3\text{CHO}\ \ +\ \ \text{HCN}\xrightarrow{\ \ \text{a}+ }\ \ \text{CH}_3-\text{CH}-\text{CN}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
→$\text{CH}_3\text{CHO}\ \ +\ \ \text{HCN}\xrightarrow{\ \ \text{a}+ }\ \ \text{CH}_3-\text{CH}-\text{CN}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$