Question
Explain hybridisation in $NH _3$.
✓
Answer
In $NH _3, N$ is $s p^3$ hybridised.
The electronic configuration of N in ground state is :
Out of four $s p^3$ hybrid orbitals three are have unpaired electrons while fourth one have one 1.p electron. Three $s p^3$ hybrid orbitals of nitrogen overlapped with $1 s$ orbitals of three hybrogen atoms and form three $N - H$ bond. The repulsion between l.p-b.p is more than b.p-b.p. Hence in molecule of $NH _3$ bond order get decreased from $109.5^{\circ}$ to $107^{\circ}$ and geometry of molecule get distorted and become pyramidal.
The electronic configuration of N in ground state is :
Out of four $s p^3$ hybrid orbitals three are have unpaired electrons while fourth one have one 1.p electron. Three $s p^3$ hybrid orbitals of nitrogen overlapped with $1 s$ orbitals of three hybrogen atoms and form three $N - H$ bond. The repulsion between l.p-b.p is more than b.p-b.p. Hence in molecule of $NH _3$ bond order get decreased from $109.5^{\circ}$ to $107^{\circ}$ and geometry of molecule get distorted and become pyramidal.
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