Question
Explain recoil and recoil velocity. Derive its expression.

Answer

  • Let us consider the example of a bullet fired from a gun. When a bullet of mass nij is fired from a gun of mass $m_2$, its velocity becomes $v_2$, and its momentum becomes m . Before firing the bullet, both the gun and the bullet are at rest. Hence, total initial momentum is zero.
  • According to Newton’s third law of motion, the total final momentum also has to be zero. Thus, the forward-moving bullet causes the gun to move backward after firing.
  • This backward motion of the gun is called its recoil. The velocity of recoil, $v_2$ is such that,

  • Maharashtra Board Class 9 Science Solutions Chapter 1 Laws of Motion 19

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