Question
Explain structures of diborane.

Answer

Diborane: $B_2H_6$ is an electron-deficient compound. $B_2H_6$ has only 12 electrons $-6e^-$ from 6 H atoms and $3e^-$ each from 2B atoms. Thus, after combining with 3H atoms, none of the boron atoms has any electrons left. X-ray diffraction studies have shown the structure of diborane as:

2 boron and 4 terminal hydrogen atoms $(H_t)$ lie in one plane, while the other two bridging hydrogen atoms $(H_b)$ lie in a plane perpendicular to the plane of boron atoms. Again, of the two bridging hydrogen atoms, one H atom lies above the plane and the other lies below the plane. The terminal bonds are regular two-centre two-electron $(2c - 2e^-)$ bonds, while the two bridging (B-H-B) bonds are three-centre two-electron $(3c - 2e^-)$ bonds.

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