Question
Explain the classification of amine compounds.
✓
Answer
$\rightarrow$ Amine compounds are classified as primary $(1^0)$ secondary $(2^0)$ and tertiary $(3^0)$ depending upon the number of hydrogen atoms replaced by alkyl or aryl groups in ammonia molecule.
$\rightarrow$ If one hydrogen atom of ammonia is replaced by $R$ or $Ar,$ we get $RNH_2$ or $ArNH_2$ a primary amine $(10)$
$\rightarrow$ If two hydrogen atoms of ammonia or one hydrogen atom of $R - NH_2$ are replaced by another alkyl/aryl $(R \ ')$ group we get secondary amine $\left(2^0\right) R - NH - R ^{ \ \prime}$
$\rightarrow$ The second alkyl/aryl group may be same or different
$\rightarrow$ Replacement of another hydrogen atom by alkyl/aryl group leads to the formation of tertiary amine $\left(3^0\right)$.
Primary $\left(1^{\circ}\right)$ secondary $\left(2^{\circ}\right)$ tertiary $\left(3^{\circ}\right)$
$\rightarrow$ Amines are said to be 'simple' when all the alkyl or aryl groups are the same, and 'mixed' when they are different.
$\rightarrow$ If one hydrogen atom of ammonia is replaced by $R$ or $Ar,$ we get $RNH_2$ or $ArNH_2$ a primary amine $(10)$
$\rightarrow$ If two hydrogen atoms of ammonia or one hydrogen atom of $R - NH_2$ are replaced by another alkyl/aryl $(R \ ')$ group we get secondary amine $\left(2^0\right) R - NH - R ^{ \ \prime}$
$\rightarrow$ The second alkyl/aryl group may be same or different
$\rightarrow$ Replacement of another hydrogen atom by alkyl/aryl group leads to the formation of tertiary amine $\left(3^0\right)$.
Primary $\left(1^{\circ}\right)$ secondary $\left(2^{\circ}\right)$ tertiary $\left(3^{\circ}\right)$
$\rightarrow$ Amines are said to be 'simple' when all the alkyl or aryl groups are the same, and 'mixed' when they are different.
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