Question
Explain the effect of substitutents on the basic strength of aromatic amines.
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Match the graph given in Column I with the order of reaction given in Column II. More than one item in Column I may link to the same item of Column II.
Column I | Column II | ||
(i) |  | ||
(ii) |  | (a) | Ist order |
(iii) |  | (b) | Zero order |
(iv) |  |
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A hydrocarbon 'A', (C4H8) on reaction with HCl gives a compound 'B', (C4H9Cl), which on reaction with 1 mol of NH3 gives compound 'C', (C4H11N). On reacting with NaNO2 and HCl followed by treatment with water, compound 'C' yields an optically active alcohol,'D'. Ozonolysis of 'A' gives 2 mols of acetaldehyde. Identify compounds 'A' to 'D'. Explain the reactions involved.
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The decomposition of a hydrocarbon follows the equation.
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Calculate Ea.
Match the items of Column I and Column II on the basis of data given below:
$\text{E}^{\ominus}_{\text{F}_2/\text{F}^-}=2.87\text{V},\text{ E}^{\ominus}_{\text{Li}^+/\text{Li}}=-3.5\text{V},\text {E}^{\ominus}_{\text{Au}^{3+}/\text{Au}}=1.4\text{V},\text{ E}^{\ominus}_{ \text{Br}_2/\text{Br}^-}=1.09\text{V}$
→$\text{E}^{\ominus}_{\text{F}_2/\text{F}^-}=2.87\text{V},\text{ E}^{\ominus}_{\text{Li}^+/\text{Li}}=-3.5\text{V},\text {E}^{\ominus}_{\text{Au}^{3+}/\text{Au}}=1.4\text{V},\text{ E}^{\ominus}_{ \text{Br}_2/\text{Br}^-}=1.09\text{V}$
| Column I | | Column II | |
| i. | F2 | a. | Metal is the strongest reducing agent. |
| ii. | Li | b. | Metal ion which is the weakest oxidising agent. |
| iii. | Au3+ | c. | Non metal which is the best oxidising agent. |
| iv. | Br- | d. | Unreactive metal. |
| v. | Au | e. | Anion that can be oxidised by Au3+ |
| vi. | Li+ | f. | Anion which is the weakest reducing agent. |
| vii. | F- | g. | Metal ion which is an oxidising agent. |
Derive formula for degree of dissociation and degree of condensation of the solute in the solvent.