Question
Explain the following:
Boron does not exist as $B^{3+}$ ion.
Boron does not exist as $B^{3+}$ ion.
✓
Answer
Boron has three electrons in the valence shell. Because of its small size and high sum of the first three ionisation enthalpies $(\text{i.e.,}\triangle_\text{i}\text{H}_1+\triangle_\text{i}\text{H}_2+\triangle_\text{i}\text{H}_3),$ boron does not lose all its valence electrons to form $B^{3+}$ ions.
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