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Electrolysis — Chemistry STD 10 — Question

ICSE BoardEnglish MediumSTD 10ChemistryElectrolysis3 Marks
Question
Explain the following :
(i) Carbon tetrachloride does not conduct electricity.
(ii) During electrolysis of lead bromide, graphite anode is peferred to other electrodes.
(iii) The electrical conductivity of acetic acid is less in comparison to electrical conductivity of dilute sulphuric acid at a given concentration.
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Answer

(i) Carbon tetrachloride is a covalent compound and hence does not have free ions which are responsible for the conduction of current through a liquid.
(ii) Bromide ions discharge at anode to form bromine gas. This gas is highly corrosive and reacts with metallic anode. To avoid corrosion of anode, graphite is preferred as it does not react with bromine and is a good conductor of electricity.
(iii) The acetic acid molecules dissociate very little (about 4%) compared to sulphuric acid molecules (about 90%). Thus, electrical conductivity of dilute acetic acid is less than dilute sulphuric acid.

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