Question
Explain the following:
$\mathrm{PbX}_2$ is more stable than $\mathrm{PbX}_4$.
$\mathrm{PbX}_2$ is more stable than $\mathrm{PbX}_4$.
✓
Answer
Due to inert pair effect, +2 oxidation state of Pb is more stable than its +4 oxidation state. Consequently, PbX 2 in which the oxidation state of Pb is +2 is more stable than $\mathrm{PbX}_4$ in which the oxidation state of Pb is +4 .
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