Question
Explain the following processe with a suitable example in case:
Chain growth polymerization.
Chain growth polymerization.
✓
Answer
Chain growth polymerisation: This type of polymerisation involves the initial formation of a free radical or an ion (from small amount of initiator such as organic peroxide) to which monomers get added up by a chain reaction. Here, the polymers are exact multiples of organic monomeric molecules and have only carbon atoms in their main chain. Various steps involved in chain growth polymerisation of ethene are:
- $\text{Initiator}\ \ \ \xrightarrow[\text{split up}]{\ \ \text{Heat, light, etx.}\ \ \ \ }\ \ \ \stackrel{{\cdot}}{\hbox{A}}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^{\text{Free redical}}$
- $\stackrel{{\cdot}}{\hbox{A}}+\text{CH}_2=\text{CH}_2\xrightarrow{\ \ \ \ \ \ \ \ \ \ }\text{A}-\text{CH}_2-\stackrel{{\cdot\ \ \ \ \ \ }}{\hbox{CH}_2}\\ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{Monomer} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(Intermediate species)}$
- $\text{A}-\text{CH}_2-\stackrel{{\cdot}\ \ \ \ \ \ }{\hbox{CH}_2}+\text{CH}_2=\text{CH}_2\xrightarrow{\ \ \ \ \ \ }\text{A}-\text{CH}_2-\text{CH}_2-\text{CH}_2-\stackrel{{\cdot\ \ \ \ \ \ }}{\hbox{CH}_2}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{Monomer}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(Bigger intermediate spwcies)}$
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