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PART - 2 CH - 11 Thermodynamics — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsPART - 2 CH - 11 Thermodynamics2 Marks
Question
Explain the isobaric process.
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Answer

Isobaric process : The process on which the pressure of the system remains constant i.e. $P =$ constant is called isobaric process. Change of state of Liquids (solid to liquid, liquid to gas or vice versa) is an example of isobaric process. If the volume $V _1$ changes to $V _2$ in the process, then the work done by the gas is:
$\begin{array}{l}\Delta W =\int_{ V _1}^{ V _2} P d V= P \int_{ V _1}^{ V _2} d V \\ \Delta W = P \left( V _2- V _1\right)\end{array}$
From first law of thermodynamics
$\Delta Q =d U + P \left( V _2- V _1\right)$

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