Question
Explain the process of leakage of electric charge.
✓
Answer
→ Capacitance $C =\frac{ Q }{ V }$
→ The above equation shows that to get a larger value of $C$, for the given value of charge $Q$, value of electric potential should be smaller.
→ This means that a capacitor with a larger capacitance can store large quantity of electric charge for a comparatively smaller electric potential V. But if the p.d. is more, then the electric field in the surrounding region of the conductor is strong.
→ If the air molecules in the surrounding region can be ionized using this strong electric field, the electric charges created by it do motion (/ accelerated motion) towards the capacitor plate, thereby neutralizeing the charge on the capacitor plates.
→ Therefore, the charge of the capacitor leaks away due to the reduction in insulating power of the intervening medium.
→ The above equation shows that to get a larger value of $C$, for the given value of charge $Q$, value of electric potential should be smaller.
→ This means that a capacitor with a larger capacitance can store large quantity of electric charge for a comparatively smaller electric potential V. But if the p.d. is more, then the electric field in the surrounding region of the conductor is strong.
→ If the air molecules in the surrounding region can be ionized using this strong electric field, the electric charges created by it do motion (/ accelerated motion) towards the capacitor plate, thereby neutralizeing the charge on the capacitor plates.
→ Therefore, the charge of the capacitor leaks away due to the reduction in insulating power of the intervening medium.
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