Question
Explain the relation in phase between displacement, velocity and acceleration in S.H.M., graphically as well as theoretically.
✓
Answer
If displacement: 
velocity $\text{v}=\omega\text{A}\cos(\omega\text{t}+\phi_0)$ 
acceleration $\text{a}=-\omega^2\text{A}\sin(\omega\text{t}+\phi_0)$ 
x and v differ in phase by $\frac{\pi}{2}.$ v and a differ in phase by $\frac{\pi}{2}.$
$\text{y = A}\sin(\omega\text{t}+\phi_0)$
velocity $\text{v}=\omega\text{A}\cos(\omega\text{t}+\phi_0)$ acceleration $\text{a}=-\omega^2\text{A}\sin(\omega\text{t}+\phi_0)$ x and v differ in phase by $\frac{\pi}{2}.$ v and a differ in phase by $\frac{\pi}{2}.$Need a full question paper?
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