- Aa = 0.7x
- Ba = -200x2
- Ca = -10x
- Da = 100x3
469 questions across 7 question groups — pick any mix to generate a Physics paper with step-by-step answer keys.
M.C.Q (1 Marks)
82 Q→02Fill In The Blanks[1 Marks ]
18 Q→031 Marks Question
136 Q→042 Marks Questions
57 Q→053 Marks Question
77 Q→064 Marks Question
5 Q→075 Marks Questions
94 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
$\text{y}=4\cos^2\Big(\frac{\text{t}}{2}\Big)\sin(1000\text{t})$
This expression may be considered to be a result of the superposition of _______ independent harmonics.A hydrogen molecule rotating about its centre of mass.
At 4cm away from B going towards A.
A man with a wristwatch on his hand falls from the top of a tower. Does the watch give correcttime during the free fall?
Time period of a particle in SHM depends on the force constant k and mass m of the particle: $\text{T}=2\pi\sqrt{\frac{\text{m}}{\text{k}}}.$ A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?
At the maximum stretched position.
In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase?$\text{x}=-2\sin\Big(3\text{t}+\frac{\pi}{3}\Big)$
The motion of a simple pendulum is approximately simple harmonic for small angle oscillations. For larger angles of oscillation, a more involved analysis shows that T is greater than $2\pi\sqrt{\frac{\text{l}}{\text{g}}}.$ Think of a qualitative argument to appreciate this result.
$\text{x}=3\sin\Big(2\pi\text{t}+\frac{\pi}{4}\Big)$
Damped oscillations
We know that the motion of a simple pendulum, swinging in air, dies out eventually. Why does it happen? This is because the air drag and the friction at the support oppose the motion of the pendulum and dissipate its energy gradually. The pendulum is said to execute damped oscillations. In damped oscillations, the energy of the system is dissipated continuously; but, for small damping, the oscillations remain approximately periodic. The dissipating forces are generally the frictional forces. The damping force is generally proportional to velocity of the bob and acts opposite to the direction of velocity. If the damping force is denoted by Fd, we have Fd = –bv where the positive constant b depends on characteristics of the medium (viscosity, for example) and the size and shape of the block, is usually valid only for small velocity.
The force producing a resistance to the oscillation is called damping force.




$\Rightarrow\text{a}=-\text{kx}$ or $\frac{\text{d}^2\text{x}}{\text{dt}^2}=-\text{kx},$
where x = displacement at any instant t.$\frac{\text{d}^2\text{x}}{\text{dt}^2}=-\omega^2\text{x}$
$\frac{\text{d}^2\text{x}}{\text{dt}^2}=-\omega^2\text{t}$
$\frac{\text{d}^2\text{x}}{\text{dt}^2}=-\omega\text{x}$
$\frac{\text{d}^2\text{x}}{\text{dt}^2}=-\omega\text{t}$
$\text{x}=\text{A}\cos\omega\text{t}+\text{B}\sin\omega\text{t}$
$\text{x}=\text{A}\cos(\omega\text{t}+\alpha)$
$\text{x}=\text{B}\sin(\omega\text{t}+\beta)$
$\text{x}=\text{A}\sin\omega\text{t}\cos^2\omega\text{t}$
$\text{x(t)}=\text{A}\cos(\omega\text{t}+\phi).$
If the initial (t = 0) position of the particle is 1cm and its initial velocity is
$\omega\text{ cm/s,}$ what are its amplitude and initial phase angle? The angular frequency of the particle is $\pi\text{s}^{-1}.$ If instead of the cosine function, we choose the sine function to describe the SHM: $\text{x}=\text{B}\sin(\omega\text{t}+\alpha),$ what are the amplitude and initial phase of the particle with the above initial conditions.Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.