Question
Explain why finely divided substance is more effective as adsorbent?
✓
Answer
- Adsorption is a surface phenomenon and hence, the extent of adsorption depends upon surface area of the adsorbent.
- Adsorption increases with increase in surface area of the adsorbent.
- Finely divided powdered substances provide larger surface area for a given mass.
Hence, finely divided substance is more effective as adsorbent.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Identify primary, secondary, tertiary and quaternary carbon in the following compounds.
Round off each of the following quantities to three significant figures :
a. $1.43 cm^3$
b. $458 \times 10^2 cm$
c. $643 cm^2$
d. $0.039 m$
e. $6.398 \times 10^{-3} km$
f. $0.0179 g$
g. $79,000 m$
h. $42,150$
i. $649.85$
j. $23,642,000 mm$
k. $0.0041962 kg$
→a. $1.43 cm^3$
b. $458 \times 10^2 cm$
c. $643 cm^2$
d. $0.039 m$
e. $6.398 \times 10^{-3} km$
f. $0.0179 g$
g. $79,000 m$
h. $42,150$
i. $649.85$
j. $23,642,000 mm$
k. $0.0041962 kg$
Identify the $\alpha -$carbons in the following species and give the total number of α-hydrogen in each.
→Given the equilibrium reaction, $H _2 O _{( g )}+ CH _{4( g )} \rightleftharpoons CO _{( g )}+3 H _{2( g )}$ Using Le Chatelier's principle, predict how concentration of $CO$ will change when the equilibrium is disturbed by
i. adding $CH _4$
ii. adding $H _2$
iii. removing $H _2 O$
iv. removing $H _2$
→i. adding $CH _4$
ii. adding $H _2$
iii. removing $H _2 O$
iv. removing $H _2$
What are real gases?
What leads to the phenomena called effective nuclear charge and screening effect in an atom?
i. Define cis- and trans-isomer.
ii. Draw geometrical isomers of but-2-ene.
ii. Draw geometrical isomers of but-2-ene.
Classify the following unbalanced half equations as oxidation and reduction.
NaCl is an ionic compound but $LiCl$ has some covalent character, explain.
→Lithium amide $\left( LiNH _2\right)$ is very strong base and it reacts with terminal alkynes to form lithium acetylides with the liberation of hydrogen indicating acidic nature of terminal alkynes. Why is it so?
→