Question
Express in terms of $\log 2$ and $\log 3$ : $\log 36$

Answer

$\log 36 = \log( 2 \times 2 \times 3 \times 3 )$
$= \log( 2^2 \times 3^2 )$
$= \log( 2^2 ) + \log( 3^2 ) ....[ \log_amn = \log_am + \log_an ]$
$= 2\log2 + 2\log3 .....[ \log_am^n = n\log_am ]$

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