Question
Express the complex number $\left(-2-\frac{1}{3} i\right)^3$ in the form of $a+i b$.

Answer


$\begin{array}{l}\left(-2-\frac{1}{3} i\right)^3=-\left(2+\frac{1}{3} i\right)^3 \\ 
=-\left[(2)^3+\left(\frac{1}{3} i\right)^3+3 \times(2)^2 \times \frac{1}{3} i+3 \times 2 \times\left(\frac{1}{3} i\right)^2\right]\end{array}$
$\begin{array}{l}=-\left[8+\frac{1}{27} i^3+4 i+\frac{2}{3} i^2\right]=-\left[8-\frac{1}{27} i+4 i-\frac{2}{3}\right]\left[\begin{array}{c}\because i^3=-i \\ i^2=-1\end{array}\right] \\
=\left[\left(8-\frac{2}{3}\right)+\left(4-\frac{1}{27}\right) i\right. \\ 
=-\left[\frac{22}{3}+\frac{107}{27} i\right]=\frac{-22}{3}-\frac{107}{27} i\end{array}$

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