Question
Express the following numbers to the lowest form: $\frac{132}{-428}$

Answer

Lowest form of: $\frac{132}{-428}$ is:
$132=2\times3\times2\times11$
$428=2\times2\times107$
$HCF$ of $132$ and $428$ is $4$.
Dividing the fraction by $4$, We get: $\frac{33}{-107}$

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