MCQ
Expression representing the cell potential $(E\,\,cell)$
- A$E_{cathode} + E_{anode}$
- B$E_{anode} -E_{cathode}$
- ✓$E_{cathode} -E_{anode}$
- D$E_{left} -E_{right}$
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(Given atomic number: $\mathrm{C}: 6, \mathrm{Na}: 11, \mathrm{O}: 8$, $\mathrm{Fe}: 26, \mathrm{Cr}: 24 \mathrm{~J}$
$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ are $(n +1)$
$(b)$ When $F_2$ reacts with $H_2O$ it forms $HF,$ $O_2$ & $O_3.$
$(c)$ $XeF_6$ on hydrolysis shows disproportionation reaction
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al (OH)_3$ as a final product