Question
Extensive properties depend on the quantity of matter but intensive properties do not. Explain whether the following properties are extensive or intensive. Mass, internal energy, pressure, heat capacity, molar heat capacity, density, mole fraction, specific heat, temperature and molarity.

Answer

Mass: ExtensiveDividing in half a tank of air at a given T,P and mass yields two smalller tanks containing air, but the mass of the air in each new, smaller tank is half as it was initially in the one big tank.
Internal energy: Extensive
Dividing in half a tank of water at a given T,P with a given total internal energy yields two smalller tank containing water at the same T and P, but the internal energy of the water in each new, smaller tank is half as it was initially in the one big tank.
Pressure: Intensive
The ratio of two extensive properties is also intensive
$\text{Pressure}=\frac{\text{Force}}{\text{Area}}=\frac{\text{Extensive}}{\text{Extensive}}=\text{Intensive}$
Heat capacity: Extensive
A sample containing twice the amount of substance as another sample requires the transfer of twice the amount of heat to achieve the same change in temperature.
Density: Intensive
$\text{Density}=\frac{\text{Mass}}{\text{Volume}}=\frac{\text{Extensive}}{\text{Extensive}}=\text{Intensive}$
Mole fraction: Intensive
$\text{Mole}\ \text{fraction}=\frac{\text{Moles}}{\text{Total}\ \text{moles}}=\frac{\text{Extensive}}{\text{Extensive}}=\text{Intensive}$
Specific heat: Intensive
$\text{Specific}\ \text{heat}=\frac{\text{Heat}\ \text{capacity}}{\text{Mass}}=\frac{\text{Extensive}}{\text{Extensive}}=\text{Intensive}$
Temperature: Intensive
Dividing in half a tank of water at a given temperature yields two smaller tanks containing water at the same temperature as that in the big tank.
Molarity: Intensive
$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}=\frac{\text{Extensive}}{\text{Extensive}}=\text{Intensive}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Nitric oxide reacts with $Br_2$ and gives nitrosyl bromide as per reaction given below:
$2\text{NO (g) + Br}_2\text{ (g)}\leftrightharpoons2\text{NOBr (g)}$
When $0.087$ mol of $NO$ and $0.0437$ mol of $Br _2$ are mixed in a closed container at constant temperature, $0.0518$ mol of $NOBr$ is obtained at equilibrium. Calculate equilibrium amount of $NO$ and $Br _2$.
The electron energy in hydrogen atom is given by $\text{E}_{\text{n}}=\frac{ (–2.18 \times 10–18 )}{\text{n}^2}\text{J}.$ Calculate the energy required to remove an electron completely from the n = 2 orbit. What is the longest wavelength of light in cm that can be used to cause this transition?
  1. Identify the oxidising agent and reducing agent in the following reactions:
  1. $\text{MnO}_2+4\text{HCl}\xrightarrow{ \ \ \ \ \ \ \ }\text{MnCl}_2+\text{Cl}_2+2\text{H}_2\text{O}$
  2. $2\text{MnO}_4^-10\text{Cl}^-+16\text{H}^+\\ \xrightarrow{ \ \ \ \ }2\text{Mn}^{2+}+5\text{Cl}_2+8\text{H}_2\text{O}$
  1. Calculate the oxidation number of underlined elements in the following speries.
$\text{Pb}_3\text{O}_4,$ $\text{H}_2\text{Cl}$, $\text{PO}_4^{3-}$
Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be represeted as $\text{v}=3.29\times10^{15}(\text{Hz})\Big[\frac{1}{3^2}-\frac{1}{\text{n}^2}\Big]$
Calculate the value of n if the transition is observed at 1285nm. Find the region of the spectrum.
Discuss the principle and method of softening of hard water by synthetic ionexchange resins.
Balance the following equations in basic medium by ion-electron method and oxidation number methods and identify the oxidising agent and the reducing agent.$N_2H_4(l) + ClO_3^-(aq) \rightarrow NO(g) + Cl^-(g)$
  1. Define an ideal gas.
  2. Define boiling point of a liquid.
  3. Which will have higher viscosity Glycerol or ethylene glycol and why?
  4. What are real gases?
  5. What do you understand by the term laminar flow?
What is the significance of the terms — ‘isolated gaseous atom’ and ‘ground state’
while defining the ionization enthalpy and electron gain enthalpy?
Hint : Requirements for comparison purposes.
For the reaction: $\text{N}_2(\text{g})+3\text{H}_2(\text{g})\rightleftharpoons2\text{NH}_3(\text{g})$at 400K, $K_p = 41$. Find the value of $K_p$ for each of the following reactions at the same temperature.
  1. $\text{2NH}_3(\text{g})\rightleftharpoons\text{N}_2(\text{g})+3\text{H}_2(\text{g})$
  2. $\frac{1}{2}\text{Na}(\text{g})+\frac{3}{2}\text{H}_2(\text{g})\rightleftharpoons\text{NH}_3(\text{g})$
  3. $2\text{N}_2(\text{g})+6\text{H}_2(\text{g})\rightleftharpoons4\text{NH}_3(\text{g})$
The pH of $0.005M$ codeine $(C_{18}H_{21}NO_3)$ solution is $9.95$. Calculate its ionization constant and $pK_b$.