MCQ
Extra pure $N_2$ can be obtained by heating :-
- A$NH_4NO_2$
- B$(NH_4)_2Cr_2O_7$
- ✓$Ba(N_3)_2$
- D$NH_3$ with $CuO$
$2 \mathrm{NaN}_{3} \stackrel{573 \mathrm{K}}{\longrightarrow} 2 \mathrm{Na}+3 \mathrm{N}_{2}$
Azide salt of barium can be obtained in the purest form as well as the decomposition product contains solid Ba as a by-product along with gaseous nitrogen, hence no additional step of
separation is required.
$\mathrm{Ba}\left(\mathrm{N}_{3}\right)_{2} \stackrel{\text { heat }}{\longrightarrow} \mathrm{Ba}+3 \mathrm{N}_{2}$
Hence, option $\mathrm{C}$ is correct.
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$(a)$ $PCl_5$ form weak monobasic acid during hydrolysis
$(b)$ In $B_3N_3H_6$ nucleophile attack on $B-$ atom
$(c)$ $Al_2Cl_6$ is a polar and planar molecule
$(d)$ In $AlF_3$, hybridisation of $Al$ is $sp^2$
$C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} $ $B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C$
${H_2}O(g){\mkern 1mu} {\mkern 1mu} + {\mkern 1mu} CO{\mkern 1mu} (g){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \rightleftharpoons \,{H_2}(g)\, + \,C{O_2}(g)\, + \,Heat{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} $