MCQ
${e^y}\frac{{dy}}{{dx}} + ({e^y} + 1)\cot x = 0$ નો ઉકેલ મેળવો.
- A$({e^y} + 1)\cos x = K$
- B$({e^y} + 1){\rm{cosec}}\,x = K$
- ✓$({e^y} + 1)\sin x = K$
- Dએકપણ નહી.
==> $\log ({e^y} + 1) + \log \sin x = \log K$ ==> $({e^y} + 1)\sin x = K$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.