Factories: 40+3 x-x^2 - Vidyadip

Question

Factories:
$40+3 x-x^2$

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Answer

We have:
$40+3 x-x^2$
$=-\left(x^2-3 x-40\right)$
To factories $\left(x^2-3 x-40\right)$, we fill find two number $p$ and $q$ such $p+q=-3$ and $p q=-40$
Now,
$5+(-8)=-3 \text { and } 5 x(-8)=-40$
$=-\left(x^2+5 x-8 x-40\right)$
$=-[x(x+5)-8(x+40)]$
$=-(x-8)(x+5)$
$=(x+5)(-x+8)$

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