Question
Solve the following equations :
$\frac{b+(b+1)+(b+2)}{4}=21$
✓
Answer
$\frac{b+(b+1)+(b+2)}{4}=21$
$
\therefore \frac{b+(b+1)+(b+2)}{4} \times 4=21 \times 4
$
...[Multiplying both the sides by 4 ]
$
\begin{aligned}
& \therefore b+b+1+b+2=84 \\
& \therefore 3 b+3=84 \\
& \therefore 3 b+3-3=84-3
\end{aligned}
$
...[ Subtracting 3 from both the sides]
$\therefore 3 b=81$
$\therefore \backslash \backslash$ frac $\{3$ b\} $\{3\}=\backslash \operatorname{frac}\{81\}\{3\}[/$ latex ...[Dividing both the sides by 3 ] $\therefore b=27$
$
\therefore \frac{b+(b+1)+(b+2)}{4} \times 4=21 \times 4
$
...[Multiplying both the sides by 4 ]
$
\begin{aligned}
& \therefore b+b+1+b+2=84 \\
& \therefore 3 b+3=84 \\
& \therefore 3 b+3-3=84-3
\end{aligned}
$
...[ Subtracting 3 from both the sides]
$\therefore 3 b=81$
$\therefore \backslash \backslash$ frac $\{3$ b\} $\{3\}=\backslash \operatorname{frac}\{81\}\{3\}[/$ latex ...[Dividing both the sides by 3 ] $\therefore b=27$
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