Question
Factories:
$a^2+ 3a - 88$
$a^2+ 3a - 88$
✓
Answer
To factories $a^2+ 3a - 88,$ we will find two numbers $p$ and $q$ such that $p + q = 3$ and $pq = -88$
Now , $11 + (-8) = 3$
And $11 x (-8) = -88$
Splitting the middle term $3a$ in the given quadratic as $11a - 8a$, we get:
$a^2+ 3a - 88 = a^2+ 11a - 8a - 88$
$= (a^2+ 11a) - (8a + 88)$
$= a(a + 11) -8(a + 11)$
$= (a - 8)(a + 11)$
Now , $11 + (-8) = 3$
And $11 x (-8) = -88$
Splitting the middle term $3a$ in the given quadratic as $11a - 8a$, we get:
$a^2+ 3a - 88 = a^2+ 11a - 8a - 88$
$= (a^2+ 11a) - (8a + 88)$
$= a(a + 11) -8(a + 11)$
$= (a - 8)(a + 11)$
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