Question
Find the product:
$-11 y^2(3 y+7)$
$-11 y^2(3 y+7)$
✓
Answer
To find the product, we will use distributive law as follows:
$-11 y^2(3 y+7)$
$=\left(-11 y^2\right) \times 3 y+\left(-11 y^2\right) \times 7$
$=(-11 \times 3)\left(y^2 \times y\right)+(-11 \times 7) \times\left(y^2\right)$
$=(-33)\left(y^2+1\right)+(-77) \times\left(y^2\right)$
$=-33 y^3-77 y^2$
Thus, the answer is $-33 y^3-77 y^2$.
$-11 y^2(3 y+7)$
$=\left(-11 y^2\right) \times 3 y+\left(-11 y^2\right) \times 7$
$=(-11 \times 3)\left(y^2 \times y\right)+(-11 \times 7) \times\left(y^2\right)$
$=(-33)\left(y^2+1\right)+(-77) \times\left(y^2\right)$
$=-33 y^3-77 y^2$
Thus, the answer is $-33 y^3-77 y^2$.
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