Question
Factorise:
$1+2 a b-\left(a^2+b^2\right)$
$1+2 a b-\left(a^2+b^2\right)$
✓
Answer
$1+2 a b-\left(a^2+b^2\right)$
$=1-\left(a^2+b^2-2 a b\right)$
$=(1)^2-(a-b)^2$
$=[1-(a-b)][1+(a-b)]$
$=(1-a+b)(1+a-b)$
$=1-\left(a^2+b^2-2 a b\right)$
$=(1)^2-(a-b)^2$
$=[1-(a-b)][1+(a-b)]$
$=(1-a+b)(1+a-b)$
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