Question
Factorise: $1 + b^3 + 8c^3 - 6bc$

Answer

$1 + b^3 + 8c^3 - 6bc$
$= (1)^3 + (b)^3 + (2c)^3 - 3 \times 1 \times b \times 2c$
$= (1 + b + 2c)[1^2 + b^2 + (2c)^2 - 1 \times b - b \times 2c - 1 \times 2c]$
$= (1 + b + 2c)(1^2 + b^2 + 4c^2 - b - 2bc - 2c)$

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